How do I prepare 0.2M of NAOH in a 250ml volumetric flask? - ECHEMI.com (2024)

FAQs

What is the mass of NaOH needed to prepare 250 mL of 0.2 M solution? ›

1/4 of litre 0.2 M contains 0.2/4=0.05 moles of NaOH. The molecular mass of NaOH is 40 g/mole therefore: 40x0. 05 = 2 g of NaOH. Thus, you have to weigh 2.000 g of NaOH and dissolve them in a 250 ml volumetric flask by feeding water until to reach the mark.

The molar mass of NaOH is 40 grams/mol. Now to prepare a 1M NaOH solution we need 40 grams of NaOH. Thus to prepare a 0.2M NaOH solution we need 40×0.2=8 grams of NaOH. Thus 8 grams of NaOH should dissolve in 1000mL water to form a 0.2M NaOH solution.

The molecular weight of NaOH is 40 g/mole. To make 250 mL of a 0.1 M solution you need 4g/4 (250 mL is 1/4 of a liter) mol or 1 g of NaOH. So, first weigh out 1 g. Next, fill a 250 mL volumetric about 2/3–3/4 full and add the NaOH to it, slowly and with stirring.

Weigh 2g of NaOH into a beaker, add distilled water to disolve it. Transfer the dislved mass of NaOH into 250mL standard volumetric flask.

0.2 m NaOH solution means 0.2 molal NaOH solution. That means, 1 Kg of NaOH solution contains 0.2 moles of NaOH. If you ask to calculate the mass of NaOH in 1dm^3 0.2 M NaOH solution, it can be answered. 1 dm^3 0.2 M NaOH solution contains 0.2 moles of NaOH = 0.2×40 = 8.0 g of NaOH.

0.1 mole/L * 0.250 L = 0.025 moles (of NaOH). 0.025 moles * 40 g/mol = 1 g.

Amount of sodium hydroxide present in 500ml of 0.2M solutions is : 4 gm.

To neutralize 40.0 mL of a 0.1 M HCl(aq), the volume of 0.2 M NaOH(aq) required is : 10.0 mL.

Preparation of 0.1 M NaOH

0.1 molar solution can be obtained either by dissolving 0.4 g in 100 mL water or by diluting 1 M solution 10 times. Note: NaOH is a secondary standard solution so standardization is required to prepare exact concentration.

Substitute the values of molarity, volume, molar mass in the above equation. 250 mL of 0.5 M sodium hydroxide solution can be prepare by taking 5.0 g of sodium hydroxide pallets in a 250 mL standard flask and adding water in it up to the mark.

How to prepare 0.1 M of NaOH in 500ml? ›

Plug in the values: mass = 0.1 mol/L × 0.5 L × 39.997 g/mol = 1.99985 g (rounded to 2 decimal places). Measure out 2.00 g of solid NaOH using a balance. Dissolve the 2.00 g of NaOH in approximately 400 mL of distilled water in a 500 mL volumetric flask.

The molarity of a NaOH solution if 250 mL contains 1 mg of NaOH is 10-4 M. Molarity is defined as the number of moles of solute in 1 litre of solution. It is the most widely used concentration unit and is represented as M.

First, you need to know how much of NaOH is required for 0.2M of the 500 ml solution. Next, you weigh out exactly 4 g of NaOH in a small beaker quickly to prevent it from being contaminated by water vapour and CO2 of the atmosphere. Add about 100 ml of distilled water to dissolve it.

1/4 of litre 0.2 M contains 0.2/4=0.05 moles of NaOH. The molecular mass of NaOH is 40 g/mole therefore: 40x0. 05 = 2 g of NaOH. Thus, you have to weigh 2.000 g of NaOH and dissolve them in a 250 ml volumetric flask by feeding water until to reach the mark.

To make 1MNaOH solution, you have to dissolve 40.00 g of sodium hydroxide pellets in 250 ml distilled water and then make up the solution to 1 liter.

So, to prepare 250 mL 0.50M NaOH solution, the required mass of NaOH = (250/1000)*0.50*40 = 5.00 g. Molar mass of NaOH = 40 g/mol. Hope this helps.

1 Answer. 2.00 g of NaOH are needed.

You need 0.1 moles of NaOH to prepare a 500ml solution with a 0.2 M concentration. First, you need to know how much of NaOH is required for 0.2M of the 500 ml solution. Next, you weigh out exactly 4 g of NaOH in a small beaker quickly to prevent it from being contaminated by water vapour and CO2 of the atmosphere.

Expert-Verified Answer

To make a 0.15M NaOH solution in 250.00 mL, you would need 1.50 grams of solid NaOH.